spydre Posted December 27, 2013 Posted December 27, 2013 The title says it all. Higher resistance equals higher voltage for the dame taste, the same power. So how does it uuse more battery for low resistance?
dannyk Posted December 27, 2013 Posted December 27, 2013 It doesn't is the simple answer ! lower resistance allows for less voltage for the same flavour so in theory the battery lasts longer.
VaporDragon77 Posted December 27, 2013 Posted December 27, 2013 On a VV/VW unit you CAN increase battery life with LR coils. As you can set the voltage lower to achieve the same plumes. However most people dont think to lower the voltage, they use a lower resistance with the same voltage to achieve a better vape. The your coil wire can be thought of as a hallway that a mass of people(electrons) are passing through. The tighter the hallway the less traffic and the longer the room at the end stays full. Now imagine all those people running down the hallway... this is an increase in voltage. Room empties quicker... if they all walk very slowely a decrease in voltage, the room(battery) stays full longer. If we widen that hallway we tighten that hallway we have more resistance if we widen the hallway we reduce the resistance. Hope my analogy helps. cpeters1965 1
VaporDragon77 Posted December 27, 2013 Posted December 27, 2013 Forgot to mention that by widening the hallway and lowering resistance, we are emptying the room faster as well. Unless you decrease the voltage to compensate the battery will deplete at a faster rate.
spydre Posted December 27, 2013 Author Posted December 27, 2013 Bebop, Jeff, Troy, Tam, what say you? Particularly since I generally set by wattage on my MVP. Does it have something to do with amps?
dannyk Posted December 27, 2013 Posted December 27, 2013 Even setting by amps your either increasing or decreasing voltage have a look at ohms law on Google. Imagine you have a 60w lightbulb connected to a battery and it lasts 1 hour. Connect a 120w lightbulb to it, it will last 30 mins as you've doubled the load ! Connect a 30w lightbulb to it and it will last 2 hours as you've halved the load. I don't know what physics classes Vapordragon went to but I'm sure as hell glad I never went to them.
Jeffb Posted December 27, 2013 Posted December 27, 2013 With this lower resistance, more electrical current can flow through the device and in essence will drain the battery faster than a standard resistance atty. The lower the resistance of an atty the higher the wattage output. look at Ohms law: With a 1.5 ohm atty at 3.7 volts the wattage output is 9.12 watts With a 2.5 ohm atty at 3.7 volts the wattage output is 5.47 watts Compenstine and bcartervol98 2
VaporDragon77 Posted December 27, 2013 Posted December 27, 2013 Even setting by amps your either increasing or decreasing voltage have a look at ohms law on Google. Imagine you have a 60w lightbulb connected to a battery and it lasts 1 hour. Connect a 120w lightbulb to it, it will last 30 mins as you've doubled the load ! Connect a 30w lightbulb to it and it will last 2 hours as you've halved the load. I don't know what physics classes Vapordragon went to but I'm sure as hell glad I never went to them. I actually have an bachelors in applied physics so i understand the basics. And what i said before was a fact. Google it if you must. I dont however understand the need for condescending comments. You either agree with me or you dont. While disagreeing with me doesnt offend me, the condescending arrogance of your comment does. And to think i expected that everyone would remain adult. Tsk tsk.
VaporDragon77 Posted December 27, 2013 Posted December 27, 2013 Thank you jeffb. Dannyk seems to dispute my logic.
dannyk Posted December 27, 2013 Posted December 27, 2013 I actually have an bachelors in applied physics so i understand the basics. And what i said before was a fact. Google it if you must. I dont however understand the need for condescending comments. You either agree with me or you dont. While disagreeing with me doesnt offend me, the condescending arrogance of your comment does. And to think i expected that everyone would remain adult. Tsk tsk. Your explanation using hallways and people I found a little bewildering where as the way I explained it using lightbulbs was much simpler. Yes a higher resistance coil will produce less watts but who vapes a 2.5ohm coil at 3.7v it would barely get warm so you find yourself pressing the ignite button longer using more power. Swings and roundabouts springs to mind. If I offended you then I can only apologise being as you have a bachelors in physics I'm surprised you didn't know that anything expressed on a forum is just taken with a pinch of salt.
Jeffb Posted December 27, 2013 Posted December 27, 2013 Now you're changing the argument. If we insert a person's vaping habits into the equation then all bets are off. But the fact still remains. All things being equal, a LR atty will drain a battery faster than a SR atty. This is not my opinion, this Ohms law, not Ohms opinion. joe2003, Tam, VaporDragon77 and 1 other 4
dannyk Posted December 27, 2013 Posted December 27, 2013 Fair point, but when talking about batteries they are measured in mAh not ohm or watts so a 1000mAH battery will last an hour provided a 1000mAH source is connected to it regardless of voltage ! This is basic electronics !
Jeffb Posted December 27, 2013 Posted December 27, 2013 An LR atty on a 1000 mah battery will drain it faster than a SR atty on a 1000 mah battery. joe2003 1
dannyk Posted December 27, 2013 Posted December 27, 2013 Well let's do some calculations then give me 5 mins to work them out
dannyk Posted December 27, 2013 Posted December 27, 2013 So for this we will use a 900mAH battery..9 x 3.7V = 3.33wAH 3.33W - 1 hour 6.66W - 30 mins 13.32W - 15 mins Based on continuous operation. So lower wattage is better regardless of the resistance being high or low as both can be achieved on either.
Jeffb Posted December 27, 2013 Posted December 27, 2013 Yes lower wattage will drain the battery slower. SR attys will provide a lower wattage. See previous calculations.
VaporDragon77 Posted December 28, 2013 Posted December 28, 2013 The original question was in regards to Resistance not Watts. You should pay more attention dannyk. Besides you gave the same answer just worded differently. And maybe you should have taken my physics class but no doubt i would have tutored you there as well.
dannyk Posted December 28, 2013 Posted December 28, 2013 Yes it was regarding resistance however as I posted above batteries are measured in mAH. As you can achieve a low watts ratio on either LR or SR coils it really doesn't matter. However on standard batteries then yes a LR might drain it quicker whereas with a spinner or twist you can compensate by lowering the voltage. Have a good day.
spydre Posted December 28, 2013 Author Posted December 28, 2013 You know what? Just shut up arguing about it. One of the reasons I want to know is because I'm a Watts kind of gal, true, HOWEVER, I have remembered there is a tasteyourjuice.com video that goes into it in detail.
dannyk Posted December 28, 2013 Posted December 28, 2013 Good idea I will say no more on the matter. Low watts = Longer batt life
spydre Posted December 28, 2013 Author Posted December 28, 2013 (edited) Well, in a roundabout, shortened way, after my SO (see Jeff, I'm not saying hubby) failed to explain it adequately, it seems to all break down to the amps or current. LR requires more amps (current) to achieve the same voltage or wattage, thus draining the battery faster, than midrange resistance or high resistance. http://www.tasteyourjuice.com/wordpress/2013/01/02/beginners-guide-to-e-cigs-and-e-cig-tech/ Edited December 28, 2013 by spydre
Bebop Posted December 28, 2013 Posted December 28, 2013 Well, in a roundabout, shortened way, after my SO (see Jeff, I'm not saying hubby) failed to explain it adequately, it seems to all break down to the amps or current. LR requires more amps (current) to achieve the same voltage or wattage, thus draining the battery faster, than midrange resistance or high resistance. http://www.tasteyourjuice.com/wordpress/2013/01/02/beginners-guide-to-e-cigs-and-e-cig-tech/ There just so many things wrong with the way you have worded this..... I get what you are trying to say. Jeff's post at 10:23am is the correct answer to this question
spydre Posted December 28, 2013 Author Posted December 28, 2013 There just so many things wrong with the way you have worded this..... I get what you are trying to say. Jeff's post at 10:23am is the correct answer to this question But his didn't answer the wattage question. I pretty much used the same words that Phil used, while showing the math on slides.
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